How Does Reducing Earth's Gravity Affect the Time a Thrown Ball Takes to Return?

AI Thread Summary
Reducing Earth's gravity from g to g/6 significantly affects the time it takes for a thrown ball to return to the thrower. The initial reasoning suggests that time increases by a factor of 6 due to the decrease in acceleration. However, the correct approach involves using the equation v² - v₁ = at, which leads to a more accurate understanding of the relationship between velocity, acceleration, and time. The discussion emphasizes the importance of applying the correct equations in projectile motion problems. Ultimately, the conclusion is that time will indeed increase as gravity decreases.
Gear2d
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Homework Statement


If I throw a ball straight up to a height h with velocity v and it takes the ball time t to go up and back to my hands, by how much would time increase or decrease if gravity on Earth where changed from g to g/6?

Homework Equations



v = a*t

The Attempt at a Solution



I wanted make sure what I am thinking was correct. I thought about this problem as a projectile problem and said that t = (v*sin(theta))/a, where "a" is acceleration. Now since the ball was thrown straight up, I made sin(theta) to sin(90). So the problem comes out to be t=v/a, and since "a" decreases by a factor of 6 that means time increase by a factor of 6. Would this reasoning be the correct way to do it?
 
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Gear2d said:
v = a*t

Hi Gear2d! :smile:

Your reasoning and your result are right … but your initial equation is wrong.

The general equation is v2 - v1 = at …

so what do you think it is in this particular case? :smile:
 
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