Your diagram seems to be for theta = 90 degrees.Auburn2017 said:I have done that but I am not sure how to get the velocity of the mass...
yeah my figure is incorrect. Vg is the gravitational potential energyharuspex said:Your diagram seems to be for theta = 90 degrees.
For the velocity, any conservation law come to mind?
(In your 'relevant equations', I don't understand Vg=mgh. What is Vg there?)
Ok. I thought it more usual to use E or U for energy. What is the T in the preceding equation? Well, I can guess from the equation what it is, but why 'T'?Auburn2017 said:yeah my figure is incorrect. Vg is the gravitational potential energy
kinetic energy. it's just the notation we use.haruspex said:Ok. I thought it more usual to use E or U for energy. What is the T in the preceding equation? Well, I can guess from the equation what it is, but why 'T'?
Ok, so what relates that to Vg?Auburn2017 said:kinetic energy. it's just the notation we use.
U=ΔT-ΔV where V=Vg+Ve and Ve is the elastic potential energy(spring) but it isn't applicable to this problemharuspex said:Ok, so what relates that to Vg?
Let's investigate that. No spring here, so Ve is zero. What is U? Can you assign a value to it?Auburn2017 said:U=ΔT-ΔV where V=Vg+Ve and Ve is the elastic potential energy(spring) but it isn't applicable to this problem
Auburn2017 said:U=ΔE=(T2-T1)+(VG2-VG1)
There are no external forces so now work is done on the system causing E=0. I figured out how to work in on my own. Thank you for your reply.billy_joule said:That's right.
What is the value of ΔE? In other words, does any energy enter or exit the system? (you are expected to assume the nudge does not add any kinetic energy to the pendulum).