How Does the Conservation of Energy Explain the Motion of Objects Over a Pulley?

AI Thread Summary
The discussion focuses on applying the conservation of energy principle to a system involving two masses connected by a string over a pulley. For part (a), the user is confident in determining the speed of the 3.00-kg object when the 5.00-kg object reaches the ground. In part (b), there is uncertainty about using the equation 1/2*m*v^2 = m*g*h to find the maximum height of the 3.00-kg object, particularly regarding the correct value for v. The user requests clarification on the problem statement, noting the lack of a figure for better understanding. The conversation emphasizes the importance of visual aids in solving physics problems.
Leesh09
Messages
8
Reaction score
0

Homework Statement


Two objects are connected by a light string passing over a light frictionless pulley as shown
in the figure. The object of mass 5.00-kg is released from rest. Using the principle of
conservation of energy, (a) determine the speed of the 3.00-kg object just as the 5.00-kg
object hits the ground. (b) Find the maximum height to which the 3.00-kg object rises.



Homework Equations





The Attempt at a Solution


I believe I am all set with part a. My question is on part B. Is it correct to say 1/2*m*v2 = m*g*h and then use 9.8 as v also and solve for h?
 
Physics news on Phys.org
The statement of the problem is not very informative without a figure. Can you post one or at least describe what the figure shows?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top