How Does the Cross Product Determine the Perpendicularity of Angular Velocity?

AI Thread Summary
The discussion centers on the relationship between angular velocity (ω) and the cross product in determining perpendicularity to the plane of rotation. The formula V = ωr illustrates how velocity (V) relates to angular velocity and radius (r). It is suggested that the direction of ω is perpendicular to the plane of rotation because it aligns with the axis of rotation. The cross product of vsinθ and 1/r is proposed as a mathematical explanation for this perpendicularity. Overall, the discussion emphasizes the geometric and mathematical principles that define the orientation of angular velocity in rotational motion.
Miraj Kayastha
Messages
80
Reaction score
0
V = ωr

V= velocity
ω = angular velocity
r = radius

How is the direction of ω perpendicular to the plane of rotation?

Is the formula ω = vsinθ χ 1/r which is the cross product of vsinθ and 1/r the reason why ω is perpendicular to the plane of rotation?
 
Physics news on Phys.org
ω is perpendicular to the plane of rotation because it is parallel with the axis of rotation.
 
ω = (r x v)/|r|2
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Back
Top