How does the fraction x^2/(x^2-1) simplify to 1 + 1/(x^2-1)?

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This is a small step in a larger Calc problem. There's 2 problems in a row where this same arrangement popped up. I have a feeling I'm forgetting something basic. How does {\frac{{x^2 }}{{x^2 - 1}}} become 1 + \frac{1}{{x^2 - 1}} ?
 
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Use polynomial long division to divide the numerator by the denominator. This gives you quotient, 1, and a remainder, 1. Just like 5/4=1+1/4.
 
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add and subtract 1 from the numerator

then we get


\frac{x^2}{x^2 -1} = \frac{x^2 - 1 + 1}{x^2 -1} = \frac{x^2-1}{x^2-1} + \frac{1}{x^2 -1} = 1 + \frac{1}{x^2 + 1}
 
2 great answers. I knew it wasn't hard, but I'd have never come up with either of these on my own. Thanks!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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