How Does This Algebraic Equation Simplify to This Result?

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SUMMARY

The algebraic equation (k*16*10^(-6))/d^2=(k*16e-6)/(30-d)^2 simplifies to 20(3-d)^2=d^2, leading to the solution d=2. The manipulation involves canceling the k terms, reciprocating both sides, and expanding the resulting expressions. The discussion highlights the importance of careful algebraic manipulation to avoid errors in simplification.

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Homework Statement



Was just wondering how this equation:

[tex](k*16*10^(-6))/d^2=(k*16e-6)/(30-d)^2[/tex]

gets manipulated to produce this result

[tex]20(3-d)^2=d^2[/tex]

[tex]d=2[/tex]

Homework Equations


The Attempt at a Solution



I've tried manipulating it myself but it ends up with me spiraling off into pages of crap that is obviously wrong.
 
Last edited:
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Are you sure you typed that in right?

Were you trying to say this?:
(k*16*10-6)/d2 = (k*16*10-6)/(30-d)2

If so, then first you would cancel the k expressions at the top, reciprocal both sides, expand and solve for d. However, I get a different result than what you give below.
 

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