How Does Touching a Violin String Affect Its Frequency?

AI Thread Summary
Touching a violin string at L/3 creates a node, effectively dividing the string into two segments. The tension and mass of the string remain constant, allowing for the calculation of the lowest frequency produced. The fundamental frequency can be determined using the formula f1 = 1/2L sqrt[F/μ], where μ is the mass per unit length. The new length for frequency calculation is 0.22m, which corresponds to the longer segment of the string. This approach confirms the correct understanding of how touching the string alters its vibrational characteristics.
clipperdude21
Messages
48
Reaction score
0
[SOLVED] Violin String and Waves

1. A violin string of length 0.33m and mass 50g is under a tension of 40N. A violin player touches the string a distance L/3 from one end, which produces a node at that point. What is the lowest frequency that can now be produced on the string?
2. I have several equations but they involve the funamental frequency
3. I tried solving this problem using the equation f1= 1/2L sqrt[F/mew] where mew is the mass per unit length. For the L i used 0.33- 0.33/3 to get 0.22m. This is the part I am not sure about. Is this the new length or is something else up. Thanks!b]
 
Last edited:
Physics news on Phys.org
There are effectively two strings now, with the same T/mew ratio. The lowest note would be the fundamental harmonic of the longer portion.
 
great, so i did it right. Thanks!
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Effect of temperature on vibrational frequency of a violin string
Replies
5
Views
2K
Tension and frequency of a vibrating violin string
Replies
26
Views
7K
Solving Wave Speed of a Violin String
Replies
6
Views
4K
Calculating frequency of the second harmonic
Replies
2
Views
2K
How Many Vibrations Does a 880Hz Violin String Make Over 332m?
Replies
4
Views
2K
How Do You Calculate the Wavelength of Sound Waves Emitted by a Violin String?
Replies
4
Views
13K
Frequencies of the first three overtones in a string?
Replies
2
Views
2K
Finding the frequency of a string based on Mass and Tension
Replies
1
Views
3K
Violin frequencies and harmonics
Replies
2
Views
4K
Length on vibrating section of violin
Replies
4
Views
10K

Hot Threads

Recent Insights

Back
Top