How Does Water Angle in a Rotating Carousel Microwave?

AI Thread Summary
The discussion focuses on calculating the angle of the water surface in a rotating microwave carousel. The problem involves a container of water at a radius of 12.0 cm, rotating once every 7.25 seconds. To find the angle, the difference in pressure on either side of the water surface due to centripetal force is equated to the height difference of the water. The solution suggests using a rotating frame of reference, incorporating fictitious forces to apply Newton's laws effectively. Understanding these principles is crucial for solving the problem accurately.
metallica007
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Homework Statement


A small container of water is placed on a carousel inside a
microwave oven, at a radius of 12.0 cm from the center.
The turntable rotates steadily, turning through one revolu-
tion in each 7.25 s. What angle does the water surface
make with the horizontal?

Homework Equations


F=ma
a=v^2/r
v=(2pi*r)/t

The Attempt at a Solution


The problem is very challenging for me that I did not know how to start think about it!

Note: I attached the solution, could you please explain it to me:approve:
 

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Hey Metallica007,
Frankly, I did not clearly understand their solution and so I will give my attempt at it:

Consider a small volume of water in the container. Let it be a horizontally kept cylinder. Let its area be a and length be l. Since the surface is inclined both the faces of the cylinder would not have equal height of water above them. Hence they have a difference in pressure and hence force on both sides. Equate this difference to the required centripetal force. You will get the value of h/l. This is equal to the tan of the angle.
 
But the angle will change as you go away from the center but not in this case. Because they have given you that the container is small.
 
hi metallica007! :smile:

(have a pi: π and try using the X2 icon just above the Reply box :wink:)

the answer is using a https://www.physicsforums.com/library.php?do=view_item&itemid=87" of reference …

ie, you imagine that you're rotating with the turntable: then Newton's laws all work provided you add a "fictitious" force, the https://www.physicsforums.com/library.php?do=view_item&itemid=84"

so you include that centripetal force on the LHS of Ftotal = 0 :smile:

(if you don't use a rotating frame, you get the same result by putting https://www.physicsforums.com/library.php?do=view_item&itemid=27" on the RHS of Ftotal = ma :wink:)
 
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