How earth is a non-inertial frame

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parshyaa
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How (more accurately) Earth is a non inertial frame?
  • A frame of reference(FOR) will be a non-inertial when a=0 ⇔ F =0
  • Suppose a book on a table is our object and Earth as a Frame of reference, generally we take accelaration of book w.r.t Earth as 0 but more accurately it is not 0(because Earth accelarates), therefore force acting on a book will also be not equal to 0. Then how it shows that Earth is a non-inertial frame , it only tells that a ≠0 and F ≠ 0, it does not tell that if a ≠0 , F=0 or vice versa
 
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parshyaa said:
How (more accurately) Earth is a non inertial frame?
  • A frame of reference(FOR) will be a non-inertial when a=0 ⇔ F =0
Sorry , a frame of reference is non-inertial if it does not follow a=0 ⇔ F=0.
 
parshyaa said:
Sorry , a frame of reference is non-inertial if it does not follow a=0 ⇔ F=0.

A frame of reference is not inertial if it does not follow all three laws of motion. Checking the first law only is not sufficient.
 
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The Earth is not an inertial frame of reference because of its rotation which, for example, gives rise to Coriolis forces. In many experiments in small regions of space, inertial is usually a good approximation.
 
parshyaa said:
How (more accurately) Earth is a non inertial frame?
In the context of general relativity where gravity is not a force and is, instead, modeled as a geometric effect, a book on a table is subject to a net force but does not accelerate. Ergo, the Earth does not define an inertial frame.
 
Chestermiller said:
I'd like to hear what @Dale has to say about this? My understanding is that the book is accelerating radially.
Yes and no. It is at rest in an accelerating frame (the one where the surface of the Earth is at rest) and it is accelerating outward in the tangent inertial frame (the one in which a freely falling elevator would be at rest).
 
jbriggs444 said:
Yes and no. It is at rest in an accelerating frame (the one where the surface of the Earth is at rest) and it is accelerating outward in the tangent inertial frame (the one in which a freely falling elevator would be at rest).
I think you're right, but I'd like to get a second opinion from @Dale. As a relative novice to GR, I await the reply of the guru.
 
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Ooh, I've never been a guru before!

The four-acceleration is a tensor, so it is covariant and therefore is non-zero in all frames. The three-acceleration is a coordinate dependent quantity, and in the rest frame of the ground it is 0. That discrepancy does identify the rest frame of the ground as being non inertial.
 
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Dale said:
Ooh, I've never been a guru before!

The four-acceleration is a tensor, so it is covariant and therefore is non-zero in all frames. The three-acceleration is a coordinate dependent quantity, and in the rest frame of the ground it is 0. That does identify the rest frame of the ground as being non inertial.
Do you mean that there is a net force on a book due to earth(how) , and acceleration of a book with respect to Earth is 0(because book is at rest with the Earth surface). Therefore F≠0 but a=0 (therefore its a non-inertial frame)
 
parshyaa said:
Do you mean that there is a net force on a book due to earth(how) , and acceleration of a book with respect to Earth is 0(because book is at rest with the Earth surface). Therefore F≠0 but a=0 (therefore its a non-inertial frame)
Note, this answer is in the context of general relativity. Newtonian physics gives a different answer.

In GR the 4-acceleration (or proper acceleration) is the acceleration measured by an accelerometer. A book sitting on a table therefore has a 4-acceleration of 9.8 m/s^2 upwards.

The 3-acceleration (or coordinate acceleration) is the second derivative of position. So in the ground's coordinates the book's 3-acceleration is 0. So the ground's coordinates are non-inertial (in GR)
 
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What does Newtonian physics say , I think you are trying to say that with context to Newtonian mechanics Earth is a inertial frame but in context to general relativity it is a non-inertial frame
Dale said:
Note, this answer is in the context of general relativity. Newtonian physics gives a different answer.

In GR the 4-acceleration (or proper acceleration) is the acceleration measured by an accelerometer. A book sitting on a table therefore has a 4-acceleration of 9.8 m/s^2 upwards.

The 3-acceleration (or coordinate acceleration) is the second derivative of position. So in the ground's coordinates the book's 3-acceleration is 0. So the ground's coordinates are non-inertial (in GR)
 
parshyaa said:
What does Newtonian physics say , I think you are trying to say that with context to Newtonian mechanics Earth is a inertial frame but in context to general relativity it is a non-inertial frame
Yes. In Newtonian mechanics, gravity is seen as a force. The book is subject to a downward force from gravity and an upward contact force from the table upon which it rests. The net force is zero and the acceleration is zero. Newton's laws are satisfied and the frame qualifies as inertial.

At least if we ignore rotation.

The force of gravity is different from most other forces. It is proportional to the mass of the object upon which it acts. Forces with this property are called "inertial" forces. Such forces (e.g. centrifugal, Coriolis forces) can typically be eliminated by choosing a different coordinate system. This is difficult to do with gravity, but Einstein managed to do so with General Relativity.
 
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jbriggs444 said:
Yes. In Newtonian mechanics, gravity is seen as a force. The book is subject to a downward force from gravity and an upward contact force from the table upon which it rests. The net force is zero and the acceleration is zero. Newton's laws are satisfied and the frame qualifies as inertial.

At least if we ignore rotation.

The force of gravity is different from most other forces. It is proportional to the mass of the object upon which it acts. Forces with this property are called "inertial" forces. Such forces (e.g. centrifugal, Coriolis forces) can typically be eliminated by choosing a different coordinate system. This is difficult to do with gravity, but Einstein managed to do so with General Relativity.
Thanks Dale and jbriggs you both are guru ^_^ ^_^ ^_^
 
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jbriggs444 said:
Yes. In Newtonian mechanics, gravity is seen as a force. The book is subject to a downward force from gravity and an upward contact force from the table upon which it rests. The net force is zero and the acceleration is zero. Newton's laws are satisfied and the frame qualifies as inertial.

At least if we ignore rotation.

But rotation does seem like the key thing that makes the Earth frame non-inertial in Newtonian mechanics.
 
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parshyaa said:
What does Newtonian physics say , I think you are trying to say that with context to Newtonian mechanics Earth is a inertial frame but in context to general relativity it is a non-inertial frame
Yes.

In both Newtonian mechanics and GR non inertial frames have fictitious forces. These fictitious forces have the properties that they are proportional to mass, they are undetectable by accelerometers, they disappear if you change reference frames, and they don't have an equal and opposite interaction.

The difference between GR and Newtonian mechanics comes in the treatment of gravity. So gravity has three of the four properties of fictitious forces, and the fourth property goes away when considering gravity as spacetime curvature instead of a force. So GR classifies gravity as a fictitious force, and this is what leads to the different classification of inertial vs non inertial frames.