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mo0nfang
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I don't understand why electron moves this way... e.g. A light object (crampled paper) going down until gets hit by the wind will go parallel (at least a few seconds) to the wind direction ... why not with electron?
I know, I just want to give an example of a force.. I don't understand why electrons move that way... If I push a table forward, it will probably move forward (except with some uncommon circumstances)... I can't imagine pushing a table forward and then it moves left, right, or any other direction.Dale said:A B-field does not behave like wind.
vanhees71 said:The force of a moving charge in an magnetic field is given by
$$\vec{F}=q \frac{\vec{v}}{c} \times \vec{B},$$
where ##q## is the charge, ##\vec{v}## the particle's velocity, ##c## the speed of light (in a vacuum), and ##\vec{B}## the magnetic field.
This is sometimes a bit complicated to figure out. The cross product is telling you that the force is always perpendicular to the velocity of the particle and the magnetic field. You get the direction by the right-hand rule, i.e., putting the thumb of your right hand in direction of the particle's velocity and the index finger in direction of the magnetic field, then your middle finger points in the direction of the magnetic force on the particle.
Since the force is always perpendicular to the force, a magnetic field doesn't change the magnetitude of the particle's velocity but only its direction. For a homogeneous magnetic field the trajectory of the particle is a helix, i.e., it is moving with a constant component of the velocity in direction of the magnetic field, and the projection of the velocity to the plane perpendicular the field is a circle.
A B-field is not a push. It is not a wind. It is not any other mechanical analogy.mo0nfang said:I know, I just want to give an example of a force.. I don't understand why electrons move that way... If I push a table forward, it will probably move forward (except with some uncommon circumstances)... I can't imagine pushing a table forward and then it moves left, right, or any other direction.
I don't know what value will I substitute to q, v, & B to get the value of Force... Can you please give simple value of q, v, & B, as well as the solution...Dale said:A B-field is not a push. It is not a wind. It is not any other mechanical analogy.
A B-field exerts a force given by ##F=qv \times B##. That is it. If you wish to make an analogy with something else then it needs to behave approximately like that.
What do you mean by substitute a value?mo0nfang said:I don't know what value will I substitute to q, v, & B to get the value of Force... Can you please give simple value of q, v, & B, as well as the solution...
How about q = 1 C, v = 1 m/s down, and B = 1 T to the left. Then F = 1 N forwards. That would be the force on a 1 C charge falling at 1 m/s through a 1 T field.mo0nfang said:I don't know what value will I substitute to q, v, & B to get the value of Force... Can you please give simple value of q, v, & B, as well as the solution...
The motion of electrons is affected by a magnetic field due to the presence of the Lorentz force. This force acts on a moving electron in a magnetic field and causes it to change direction.
The deflection of electrons in a magnetic field is caused by the interaction between the magnetic field and the electric charge of the electron. This interaction creates a force that causes the electron's path to bend.
The amount of deflection of an electron in a magnetic field is influenced by the strength of the magnetic field, the speed of the electron, and the angle between the direction of motion and the direction of the magnetic field.
Electrons move in a circular path in a magnetic field because the force acting on them is always perpendicular to their velocity, causing them to continuously change direction and move in a circular path.
Yes, electrons can be deflected in a non-uniform magnetic field. The amount and direction of deflection will vary depending on the strength and direction of the magnetic field at different points along the electron's path.