How Far Apart Are Light Fringes in a Double Slit Experiment?

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In a double slit experiment with a wavelength of 740nm and a slit separation of 0.140mm, the calculation for the linear distance between adjacent maxima yielded an incorrect result of 2.5 kilometers. The formula used was dy/L = m*wavelength, but the application of this formula led to an unrealistic distance. The correct approach requires careful attention to unit conversions and the parameters involved. The significant error highlights the importance of double-checking calculations in physics problems. Accurate results are crucial for understanding interference patterns in such experiments.
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Homework Statement


In a double slit experiment, the wavelength is 740nm, the slit separation is 0.140mm, and the screen is 48.0cm away from the slits. What is the linear distance between adjacent maxima on the screen? Please check my answer.


Homework Equations


dy/L = m*wavelength


The Attempt at a Solution


y = [1(740x10^-9 m)(0.48m)]/(0.140x10^-3m)
y = 2.5 x 10^3 m

Thanks!
 
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hardwork said:
y = 2.5 x 10^3 m

2.5 kilometers is much too large an answer here.
 

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