How Far Can a Person Walk on an Overhanging Plank Before It Tips?

  • Thread starter Thread starter TastyTyr
  • Start date Start date
  • Tags Tags
    Dynamics
TastyTyr
Messages
7
Reaction score
1
A uniform plank of length 5.8 m and weight 216 N rests horizontally on two supports, with 1.1 m of the plank hanging over the right support (see the drawing). To what distance x can a person who weighs 441 N walk on the overhanging part of the plank before it just begins to tip?

This is what I did:

I took the weight of the plank and multiplied by the hanging support. I next set that equal to the weight of the person times x distance

So it looks like:

216(1.1)=441x
I solved for x and got
x=0.539

but it's wrong...what do I do?
 
Physics news on Phys.org
This problem begins with the realization that just before the plank tips over, the normal force from the left support vanishes. To find the position x of equilibrium, you should balance the force and the torque on the plank. Which of these two equations will be useful for finding x?
 
..and so the sum of all forces and the sum of torque should both equal zero
but do I use the torque equation at all?
T=R*F or T=F*L

was what I did at first completely wrong??
 
Well, the force equation doesn't involve x, so it can't be used to find x. I think you had the right idea above, but you excuted it incorrectly. You need to figure out the torque exerted by the left side of the board, the right side of the board, and the person. All these torques should balance in equilibrium. To find the torque you need to know the force that is creating the torque. Once you have this force, you can figure out the moment arm either by doing a simple integral or simply by guessing.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top