How far did the ball roll during the first 5 seconds of its motion?

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A ball rolls down a hill with uniform acceleration, covering 150 meters during the second 5 seconds of its motion. To find the distance rolled in the first 5 seconds, the kinematic equation S = ut + (1/2)at^2 is used, simplifying to S = (1/2)at^2 since the initial velocity is zero. The distance traveled during the second 5 seconds is calculated as the difference between the total distance in 10 seconds and the distance in 5 seconds. Solving for acceleration reveals that the previously calculated value of 3 m/s² is incorrect. Substituting the correct acceleration into the equation allows for determining the distance rolled in the first 5 seconds.
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pls. help --> acceleration

Homework Statement


a ball starts from rest and rolls down a hill with a uniform acceleration traveling 150m during the second 5.0s of its motion. How far did it roll during the first 5.0s of its motion:confused:

pls. help

Homework Equations




The Attempt at a Solution

 
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what have u tried so far so that we can help u?
 
i tried to get its acceleration and i got a 3m/s^2, but after that i don't know what to do, I'm not even sure if i got it right.
 
What you have to see first is that the distance traveled by the rolling ball in the next 5 seconds is nothing but the difference between the distance traveled by the ball in 10 seconds and the distance traveled in 5 seconds.

By the simple kinematic equation, we know that:

S=ut+(1/2)at^2

Since the initial velocity u is 0, the ut component of the equation goes and only (1/2)at^2 is left.So the distance traveled in the next 5 seconds is nothing but:

(1/2)a{(10^2)-(5^2)}=150

Solve for 'a'.(It wouldn't work out to 3m/s^2.)
Now, u know 'a' so substitute it in the equation (1/2)a.5^2 to get the answer!
 
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