How far does a car travel before reaching a speed of 100 km/h?

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A car advertised to reach 100 km/h in 11.3 seconds was initially calculated to travel approximately 21.7 meters before reaching that speed, but this was deemed too short. The correct approach involves calculating acceleration and displacement using the formula for constant acceleration, which requires stating the assumption of constant acceleration. After correcting the calculations, the displacement was recalculated to be approximately 314 meters, though the factor of 1/2 in the displacement formula was initially overlooked. The discussion emphasizes the importance of careful calculations and understanding of motion principles. Mastery of these concepts will improve with practice.
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A car is advertised as taking 11.3\ s to reach a speed of 100\ kmh^{-1}. About how far does it travel before reaching this speed?

Firstly I have tried to work out the acceleration: a=\frac{\frac{100000}{3600}}{11.3}\approx 0.2175\ ms^{-2}

I've then used this to find the displacement: x=0.2175\times 11.3^2\approx 21.7\ m

Am I doing something wrong? It seems like too short a displacement...

Thanks for your help
 
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Check your conversion from \tfrac{kilometers}{hour} to \tfrac{meters}{second}.
Remember that for motion with constant acceleration, starting at rest, S=\tfrac{1}{2} a t^2
Don't round your results so much. Keep your answer parametric until the very end. This is a skill you'll NEED once you get to the more complicated stuff.
You were off by a factor VERY different from 10^n in your calculation of the average acceleration.

Another thing I feel I should mention is that you need to state your assumption that the car accelerates with a constant acceleration, as that is not always the case, and your results will vary greatly should you consider such a case.
 
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Awesome. Thanks for your help.
I'm now getting the answer as \approx 314\ m with
a=\frac{2500}{1017}\ ms^{-2}
Is that correct?
 
Last edited:
Stroodle said:
Awesome. Thanks for your help.
I'm now getting the answer as \approx 314\ m with
a=\frac{2500}{1017}\ ms^{-2}
Is that correct?

That is very close, you forgot the factor of \tfrac{1}{2} in the displacement as a function of time formula.
 
Oh yeah. Oops.

Thanks again for your help. I'm sure these will become really easy after I do a few more of them.
 
Stroodle said:
Oh yeah. Oops.

Thanks again for your help. I'm sure these will become really easy after I do a few more of them.

Oh yeah, completely. By the time you get to the subject of work and energy, you'll be reciting these in your sleep. :)

And no problem, you're very welcome.
 
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