- #1
jacksonbobby5
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So if I have a kangaroo on planet Y with a specified gravity of 12m/s^2. If he jumps with an inital velocity of 8m/s, how far would he travel?
How Far Does a Kangaroo Jump on Planet Y?
- Thread starter jacksonbobby5
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Homework Help Overview
The discussion centers around a problem involving the jumping distance of a kangaroo on a hypothetical planet with a specified gravity. The original poster presents initial conditions including gravity and initial velocity but seeks to determine the distance traveled during the jump.
Discussion Character
- Exploratory, Assumption checking, Mathematical reasoning
Approaches and Questions Raised
- Participants discuss various kinematic equations, questioning the applicability of certain formulas given the lack of time as a variable. There is exploration of how to relate initial velocity and gravity to the distance traveled.
Discussion Status
The conversation is ongoing, with participants sharing their thoughts on different kinematic equations and their validity. Some guidance has been offered regarding the selection of appropriate equations based on known variables, but no consensus has been reached on a definitive approach.
Contextual Notes
Participants note the assumption of level ground and the absence of atmospheric resistance, which may influence the calculations. There is also a mention of needing to know the angle of the jump for further analysis.
- #2
Hootenanny
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What have you attempted thus far? What are your thoughts?
- #3
jacksonbobby5
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Well I thought I would use the formula y=Vi(time)+1/2g(time)^2, but I don't have a time, just initial velocity and gravity.
- #4
Hootenanny
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Which other kinematic equations do you know? You need to pick one with all the variables in that you know plus the one which you want to find out.jacksonbobby5 said:
- #5
jacksonbobby5
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Well, I also had read about an equation that is y=(Vi^2)/2g but I wasnt sure wether this was a valid equation or a kinematic equation. Any clue?
- #6
Hootenanny
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Sounds goot to mejacksonbobby5 said:
- #7
misnoma
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assume a level ground with no atmospheric resistance.
time of flight for the first half (rising) is t = (v-u)/g = 0.666 sec, sot he time of flight for the last half descent is also 0.666 sec. Total time is thus 1.333 sec.
with no reistance to motion in the x-axis the distance traveled is just the (X component of velocity) x time, do you know the angle?
time of flight for the first half (rising) is t = (v-u)/g = 0.666 sec, sot he time of flight for the last half descent is also 0.666 sec. Total time is thus 1.333 sec.
with no reistance to motion in the x-axis the distance traveled is just the (X component of velocity) x time, do you know the angle?