How far does a putty block compress a spring after an inelastic collision?

AI Thread Summary
A 0.440 kg block attached to a spring with a force constant of 23.0 N/m is impacted by a wad of putty weighing 5.90*10^-2 kg, moving at 2.50 m/s. After the inelastic collision, the combined system's momentum is used to calculate the final velocity. The kinetic energy of the block-putty system is then equated to the potential energy stored in the spring to determine the compression distance. The solution involves converting units from meters to centimeters for the final answer. The discussion highlights the conservation of energy principle in this collision scenario.
jwang023
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Homework Statement



A 0.440 kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 23.0 N/m. The block rests on a frictionless surface. A 5.90*10^-2 wad of puddy is thrown at the block, hitting it with a speed of 2.50 m/s and sticking. How far does the putty block system compress the spring?

Homework Equations



I wrote down the equation for springs. U= 0.5kx^2

The Attempt at a Solution



I have drawn a picture and figured out the momentum of the puddy onto the block, but not sure what to do after that.
 
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Calculate the velocity of the block-puddy system.

ehild
 
I have found the velocity of the puddy block. Trouble is, I'm having a hard time relating it back to the spring constant.
 
After collision, the forces are conservative, as the friction does not count. The block and puddy together have some kinetic energy. They push the spring and the spring exerts force on them, and the total energy of the moving mass + spring is conserved. On what depends the energy of the spring?

ehild
 
Ok I get it. I went and found the Kinetic energy of the block/puddy after I found the final velocity of the two. Since you said that they were conserved I set the K=Uspring. and solved for x after converting meters to centimeters. Thanks for the help! :)
 
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