How Far Should Goods Be Dropped from a Plane to Hit a Mountain Ridge?

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To determine how far in advance goods should be dropped from a plane to hit a mountain ridge, the height of 203 m and the plane's speed of 65.278 m/s are crucial. The horizontal distance can be calculated by first determining the time it takes for the goods to fall 203 m under gravity, assuming no air resistance. Once the fall time is established, it can be multiplied by the plane's horizontal speed to find the drop point. If the drop zone is 441 m ahead, the required vertical velocity can be calculated by adjusting the fall time to ensure the supplies reach the target. Accurate calculations are essential for successful drops in such scenarios.
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I am trying to drop goods to a ridge of a mountain. The height from the ground to the plane is 203 m. The distance from the plane to the ridge is X. If plane is traveling at 65.278 m/s, how far in advance (horizontal distance) must the goods be dropped?

-Should I calculate Vxo since Vyo would be 0? Then figure out what the horizontal distance would be?

Using same info, what if now 441 m in advance of drop zone, what vertical velocity should supplies be given to hit drop zone?
 
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The technique is generally to calculate the time the object will take to fall the appropriate distance (assuming no air resistance and falling at 'g')
You then use this time together with the constant horizontal speed to calculate the horizontal distance
 

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