How Fast Does the Rim of a Spinning Disk Travel?

AI Thread Summary
To determine the speed of a point on the rim of a spinning disk, the kinetic energy formula K=(1/2)*I*(ω^2) is used, where I is the moment of inertia and ω is the angular velocity. The moment of inertia for a thin disk is calculated as I=(1/2)*M*R^2. The user encounters difficulties in calculating the correct angular velocity and converting it to linear speed. There is a realization of a potential calculation error, prompting a reconsideration of the approach. The discussion highlights the importance of correctly applying formulas and unit conversions in physics problems.
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Problem 13.30
A thin, 60.0g disk with a diameter of 7.00 cm rotates about an axis through its center with 0.240 J of kinetic energy. What is the speed of a point on the rim?

Homework Equations


m=.06kg
r=.035m
KE=.240J

The Attempt at a Solution



K=(1/2)*I*(w^2)
I=(1/2)*M*R^2

I'm using the formula above but I'm not getting the right answer. My numbers seem way to small. I eventually get w(omega) alone. Where do I go from here. Do i need to solve for the length to figure out rad/s then convert to m/s?

Perhaps I am approaching this wrong.
 
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Calculation error, sorry. Mods you can delete.
 
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