How Fast Must a Basketball Player Jump to Reach 85.8 cm?

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To determine the initial velocity required for a basketball player to reach a height of 85.8 cm, the player must first account for the drop of 64.0 cm before jumping. The discussion highlights the challenge of calculating the initial velocity without additional information such as the time of ascent or the height from which the player jumps. The focus is on applying physics principles to solve for the required speed at takeoff. The conversation emphasizes the need for clarity in the problem setup to facilitate finding a solution. Overall, the inquiry seeks assistance in bridging the gap in understanding the dynamics of the jump.
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A 92.7 kg basketball player can leap straight up in the air to a height of 85.8 cm. The player bends his legs until the upper part of his body is dropped by 64.0cm, then he begins his jump. With what speed must the player leave the ground to reach a height of 85.8 cm?

The mass is given for the next part of the question which switches to dynamics, or at least that is my assumption. I can not seem to solve for the initial velocity as he leaves the ground because his height is not given nor the time it takes to reach the top or anything else for that matter. I can do the 2nd part on my own if only i could get this first part.

I think I am missing something obvious, any help is greatly appreciated.
-Adrian
 
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