How Fast Was the Car Going Before Skidding to a Stop?

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A physics problem involves calculating the initial velocity of a 1350 kg car that skidded for 100 meters before stopping, with a coefficient of friction of 0.55. The braking force is 9500 N, and the net force is determined by the frictional force opposing the motion. Participants discuss the correct application of formulas, including Fg and Ff, and the relationship between acceleration, displacement, and velocity. There is confusion regarding the direction of forces and the correct interpretation of acceleration units. The conversation emphasizes the need to clarify equations and calculations to solve for the initial velocity accurately.
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Dynamics physics urgent help please!

Homework Statement



A 1350 kg car narrowly avoids running off of a washed out bridge. The coefficient of friction between the car and the road is 0.55. If the skid marks are 100 meters long, what was the initial velocity of the car?


Homework Equations



Fg = mg
Ff = coefficient x Fn

The Attempt at a Solution



Find Fg
Find Ff
Find acceleration
Find final velocity
 
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shubham1 said:

Homework Statement



A 1350 kg car narrowly avoids running off of a washed out bridge. The coefficient of friction between the car and the road is 0.55. If the skid marks are 100 meters long, what was the initial velocity of the car?


Homework Equations



Fg = mg
Ff = coefficient x Fn

The Attempt at a Solution



Find Fg
Find Ff
Find acceleration
Find final velocity
shubham1, you'll have to show a bit more of an attempt. What have you tried? Show us what you've tried so we can know how to help you.
 


d = 100m
v = 0 m/s (final)
u = ? m/s (initial)

a = Look in your book for an equation relating the coefficient of friction to the mass of the object.

What is one of the kinematic equations you know relating acceleration, displacement, and velocities?
 


Important info I forgot to mention: Applied braking force is 9500 N.
I am not sure which way is the Fnet.
I found Fg, which is 13230 N downwards.
I found Ff which is 7276.50 backwards.
I found acceleration which is 12.427 N backwards.
However, my teacher told me to make the Fnet positive, but which way is the Fnet? Is it where the friction is? and also, is the Fa opposite to the Ff.
 


Fnet is probably the net force, which is going forwards. The braking force is what is slowing down the car, which is why your acceleration is going to be negative, as you said you found acceleration to be "backwards". So if acceleration is going this way <--- and is negative, and Fnet should be positive, it should be going ---> this way.
 


Fnet=ma
If a is negative (backwards), then shouldn't Fnet also be negative.
 


I think you're going to have write out what these symbols mean before it gets confusing.

This isn't as complicated as it looks, have you first considered the equation you will be using to solve for the initial velocity? When you know what equation you will use, it will be a lot clearer.
 


For sloving initial velocity, I will use Vf^2 = Vi^2 + 2ad
 


Acceleration = F/m

Where F = frictional force.

You claimed your acceleration was 12N backwards, how did you get 12 Newtons for acceleration? The unit for acceleration is not Newtons.
 
  • #10


Sorry, I meant 12.427 m/s^2 backwards.

I basically did:

Fnet = Fa + Ff (sum of all the forces)
ma = -Fa - Ff
(1350)(a) = -9500-7276.50
a = -12.427 m/s^2 backwards
 
  • #11


If the skid marks are 100 meters long,

You are not using this data
 

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