How High Does a Rocket Go If It Accelerates for 4 Seconds?

AI Thread Summary
The rocket accelerates upward at 29.4 m/s² for 4 seconds, reaching a velocity of 117.6 m/s and a position of 588 meters at the end of this period. After running out of fuel, it continues to coast upward before gravity causes it to decelerate at -9.81 m/s². To find the maximum height, the velocity at the end of the 4 seconds can be used along with energy conservation principles. The maximum height can be calculated by determining how far the rocket ascends after fuel depletion until its velocity reaches zero. The discussion emphasizes the importance of using kinematic equations and energy conservation to solve for the rocket's trajectory.
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Finding Maximum Height?

A rocket moves striaght upward, starting from rest with an acceleration of 29.4m/s^2. It runs out of fuel at the end of 4.00seconds and continues to coast upward, reaching a maximum height before falling back to Earth.

(a.) Find the rocket's velocity and position at the end of 4.00seconds.

(b.) Find the maximum height the rocket reaches.






There was ten parts to this problem and I'm stuck on how todo these to.
Thanks sooo much for the help!
 
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a) s=\frac{1}{2}at^{2}; v=at
b) at the end of the 4 seconds period, the rocket will have velocity of v (calculated above) and a downward negative acceleration of g=-9.81m/s^{2}. Do the rest yourself :)

Hint: You can also use the law of conversion of energy for the second part.
 
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