How High Does the Elevator Meet the Coin in Torronto Tower?

  • Thread starter Thread starter khurram usman
  • Start date Start date
  • Tags Tags
    Elevator Tower
AI Thread Summary
The discussion focuses on a physics problem involving an elevator in the Toronto Tower and a coin dropped from the top floor. The elevator ascends at a speed of 370 m/min, while the coin falls under the influence of gravity. To solve the problem, one must establish height vs. time equations for both the elevator and the coin. By equating these two expressions, the time at which they meet can be determined. This approach allows for calculating the height at which the elevator encounters the coin.
khurram usman
Messages
86
Reaction score
0
elevator of torronto tower...?

the elevators in the torronto tower travels at 370m/min from ground level to the top floor . suppose that when the elevator begins to rise from ground level a coin is dropped from the top floor down the elevator shaft. at what height does the elevator meet the coin?


give me a hint to how to start this question...
i know that the distance traveeld by coin is given by 1/2*a*t^2
but i can't seem think of any way to put it all together...
 
Physics news on Phys.org


Write down an expression for the height vs. time of the coin (you've already sort of done this).

Write down an expression for the height vs. time of the elevator.

When the two meet, their heights will be equal. Therefore, you should equate these two expressions and solve for the time, t, that satisfies this equation.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Calculating the Velocity of an Elevator
Replies
35
Views
5K
When will the bolt pass the elevator floor?
Replies
18
Views
4K
Relative Motion - Elevator Problem
Replies
18
Views
8K
Solving John's Elevator Problem: Acceleration & Time/Distance
Replies
11
Views
2K
Max Jumping Height in Elevator Descending at Constant Vel.
Replies
1
Views
5K
Elevator with constant acceleration
Replies
5
Views
4K
Work / Energy Elevator / Spring Problem
Replies
5
Views
4K
Heat energy in an inelastic collision
Replies
8
Views
3K
How to Determine Elevator Height at Time T1?
Replies
11
Views
6K
A glass marble is dropped down an elevator shaft
Replies
28
Views
3K

Hot Threads

Recent Insights

Back
Top