How High Should the Cable Be Anchored for Equilibrium?

AI Thread Summary
The discussion focuses on determining the minimum height for anchoring a cable to ensure equilibrium for a sign and rod system. The forces involved include the weight of the sign and the rod, with the tension in the cable needing to be factored into the torque equation. Participants emphasize the importance of calculating the torque about the pivot point, ensuring that the sum of torques equals zero. There is a need to express the vertical component of tension and the corresponding distance in the torque equation. The conversation highlights the complexities of setting up the equations correctly to solve for the height above the pivot.
jtulibarri
Messages
2
Reaction score
0
a 65 kg sign hung centered from a uniform rod of mass 9.8 kg and length 2.3 m. At one end(left) the rod is attached to the wall by a pivot; at the other end(right) it's supported by a cable that can withstand a maximum tension of 760 N. What is the minimum height h above the pivot for anchoring the cable to the wall?

14-49.gif



i need help on setting up an equation to solve...
what i have so far i don't know how wrong or right it is.


(Force of sign)(Radius of sign)+(Force of rod)(Radius of rod)-(Tension)=0
(637N)(1.15m)+(96.04N)(1.15m)-m*g*sin(angle away from wall)=0

? i don't really know exactly where I am going with this
 
Physics news on Phys.org
jtulibarri said:
(Force of sign)(Radius of sign)+(Force of rod)(Radius of rod)-(Tension)=0
(637N)(1.15m)+(96.04N)(1.15m)-m*g*sin(angle away from wall)=0

? i don't really know exactly where I am going with this

you need the torque about that point to be zero... so you need:

(Force of sign)(Radius of sign)+(Force of rod)(Radius of rod)-(vertical component of Tension)*distance=0

(since horizontal component of tension exerts 0 torque about the pivot)

what is the vertical component of Tension in terms of the total tension T... what is the distance here?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Torque and Rotational Equilibrium with a slanted Rod/Cable
Replies
7
Views
3K
Equilibrium of Forces and Torques on Sawhorses Supporting a Person on a Board
Replies
6
Views
2K
What is the Time to Pivot the Rod with a Spinning Disk?
Replies
2
Views
1K
How Do You Calculate Tension Correctly in a Pivoting Rod System?
Replies
1
Views
4K
Solving Equilibrium w/ Plank & Forces | Physics Problem
Replies
7
Views
4K
Seemingly simple equilibrium problem - force balance
Replies
6
Views
2K
Time it Takes for a Transverse Pulse to Travel a Distance "L" Up a Cable Against Gravity?
Replies
13
Views
1K
Torque and rotational equilibrium question
Replies
6
Views
4K
How Do You Calculate Forces and Balance a Hanging Cafe Sign?
Replies
18
Views
3K
Maximum tension in a cable holding a drawbridge
Replies
5
Views
2K

Hot Threads

Recent Insights

Back
Top