How High Will a Pebble Go When Shot from a Compressed Spring?

Thread starter truthisfreedom3
Start date Sep 19, 2005
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Conservation Conservation laws Laws

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To determine how high a pebble will rise when shot from a compressed spring, the potential energy stored in the spring must be calculated using the formula for spring potential energy (PE = 1/2 k x^2), where k is the spring constant and x is the compression distance. The average force of 50.0 N can help find the spring constant, and the gravitational potential energy (PE = mgh) can be used to find the height, where m is the mass of the pebble and g is the acceleration due to gravity. By equating the spring potential energy to the gravitational potential energy, the maximum height can be solved. The pebble, weighing 20.0 g, will rise to a height determined by these calculations. Understanding the energy transformation between spring potential energy and gravitational potential energy is key to solving the problem.

Sep 19, 2005

truthisfreedom3

The question I'm doing for homework that I can't get is...

A spring is compressed 10.0 cm by an average force of 50.0 N. If the spring shoots a 20.0 g pebble straight up into the air, how high will it rise?

It would be sooper awesome if you could help with this!

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Sep 19, 2005

Doc Al

Mentor

Where did you get stuck? Show your work to get help. (Hint: Spring PE gets transformed to Gravitational PE.)

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