Engineering How Is Alpha Calculated in the Discretization of an RC Circuit?

AI Thread Summary
The discussion focuses on deriving a discrete formula for voltage in an RC circuit using the forward difference approximation. The formula is expressed as Vab[k + 1] = α Vab[k], where α is calculated based on the period T, resistance R, and capacitance C. The initial calculations suggest α = (T/RC) + 1, resulting in approximately 1.0025, but the solutions manual indicates α should be 0.9975, implying a decay in voltage. This discrepancy arises from the orientation of current, which affects the sign in the differential equation. The conversation highlights the importance of understanding the circuit's behavior, particularly that α must be less than 1 for a decaying output voltage.
Feodalherren
Messages
604
Reaction score
6

Homework Statement


[/B]
Derive a discrete formula for an RC circuit for Vab[k] using the forward difference approximation. It should be of the form Vab[k + 1] = α Vab[k], and depend only on T, R, and C. For T = 0.076 s, R = 3 kΩ, and C = 10 mF, what is α?

T is the period.
The current is going from a to b.

Homework Equations



Ohms law
Forward difference formula

The Attempt at a Solution



I can't find the equation editor...

dVab(t)/dt = (1/c)I(t)

discretisized:

dVab[k]/dt = I[k]/c

which is approximately equal to

(Vab[k+1] - Vab) / T

solving for Vab[k+1]

Vab[k+1] = (T/C)I[k] + Vab[k]

From Ohm's law for a simple RC circuit we can find that

I = Vab/R

thus

Vab[k+1] = (T/RC)Vab[k] + Vab[k]

Vab[k+1] = ((T/RC)+1) Vab[k]

it follows that

α = (T/RC)+1)

which yields a result of approximately 1.0025

however, the solutions manual claims that the answer is 0.9975 which is (1-(T/RC))
 
Physics news on Phys.org
I think I solved it. I swapped
(Vab[k+1] - Vab) / T

to
(-Vab[k+1] + Vab) / T

because of the orientation of the current.
 
Feodalherren said:

Derive a discrete formula for an RC circuit for Vab[k]...
There is only ONE RC circuit in the universe? How about showing us a schematic drawing ...
The problem wording suggests that the output voltage is decaying in which case you know alpha has to be < 1.
 

Similar threads

Replies
17
Views
2K
Replies
2
Views
2K
Replies
46
Views
10K
Replies
6
Views
2K
Replies
4
Views
1K
Replies
1
Views
1K
Back
Top