How Is Angular Speed Calculated for a Pulley System?

AI Thread Summary
Angular speed for a pulley system can be calculated using the relationship v = rω, where v is the linear velocity, r is the radius, and ω is the angular speed. The discussion centers on determining the angular speed of the pulley, particularly in relation to two boxes with a common velocity. The proposed formula for angular speed is ω = (1/R) * √((2gh)(mA - mB)/(mA + mB + I/R²)). Participants confirm that the approach and calculations appear correct, emphasizing the importance of understanding the conservation of energy in this context. Accurate calculations are crucial, especially given the question's high point value.
dennislam
Messages
5
Reaction score
1

Homework Statement


problem.png


Homework Equations


v=rω
conservation of energy

The Attempt at a Solution

20161103_145743.jpg


I don't know whether it is correct or not, and I am quite confused in part b
it asks the angular speed of the pulley
can I say that v=rω since the pulley and box A,B have a common velocity?
so is ω equal to 1/R*√((2gh)(mA-mB)/(mA+mB+I/R^2))?
but the question is worth 10 marks:H
 
Physics news on Phys.org
dennislam said:

Homework Statement


View attachment 108390

Homework Equations


v=rω
conservation of energy

The Attempt at a Solution

View attachment 108391

I don't know whether it is correct or not, and I am quite confused in part b
it asks the angular speed of the pulley
can I say that v=rω since the pulley and box A,B have a common velocity?
so is ω equal to 1/R*√((2gh)(mA-mB)/(mA+mB+I/R^2))?
but the question is worth 10 marks:H
That all looks right.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
11
Views
3K
Replies
17
Views
338
Replies
3
Views
1K
Replies
1
Views
3K
Replies
1
Views
3K
Replies
9
Views
4K
Replies
3
Views
2K
Replies
11
Views
2K
Back
Top