How Is Centripetal Force Calculated for a Bird Pulling Out of a Dive?

AI Thread Summary
To calculate the centripetal force for a bird pulling out of a dive, the mass of the bird (0.211 kg), the radius of the circular arc (25.6 m), and the speed at the bottom of the arc (21.7 m/s) are essential. The centripetal force can be determined using the formula Fc = mv²/r. The discussion highlights confusion regarding the concept of "pulling out of a dive" and its relation to centripetal force. It also addresses the need to consider both the upward lift force and gravitational force acting on the bird at the bottom of the arc. Understanding the derivation of the centripetal force equation from F=MA is also a point of inquiry.
Fractal314
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1. A bird of mass 0.211kg pulls out of a dive, the bottom of which can be considered to be a circular arc with a radius of 25.6m. At the bottom of the arc, the bird's speed is a constant 21.7m/s. Determine the magnitude of the upward lift on the bird's wings at the bottom of the arc.

I am pretty sure that Fc= -4(pi squared)(r)(m)(f) / Tsquared

and... Fc= -mv squared / r

r= radius, m= mass, Fc = centripetal force

3. Ok so I don't understand what it means by "pulling out of a dive", I mean is that supposed to be part of the arc? This question is put under the heading centripetal force in my textbook but I don't understand how it is centripetal. Furthermore, if all is well, does it come down to the question being as simple as subbing in the values to the equation I have here.


Also, can anybody tell me how the centripetal force equation is derived from F=MA? I am lost on that too.:blushing:
 
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On the bottom of the dive there is the upward lift force pulling it up and also gravity pulling the bird down. so Fc= Upward lift force - Fg
 
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