How Is Coulomb's Law Demonstrated with a Suspended Charged Ball?

AI Thread Summary
Coulomb's law can be demonstrated using a lightweight, negatively charged ball suspended freely, which is repelled by a nearby negatively charged sphere. The angle of deflection, x, is measured to analyze the forces acting on the ball. The weight of the ball (W) and the force of repulsion (F) are related through the equation F = W tan x. To derive this, one must consider the components of the normal reaction force and apply equilibrium conditions, ensuring the sum of forces is zero. Understanding the normal force and its components is crucial for solving the problem effectively.
rindishy123
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Hey...i need help...


"One practical arrangement for verifying Coulomb's law is to use a lightweight, negatively charged, freely-suspended ball. it is repelled by the negative charge on a larger sphere that is held near it, on an insulated support. the small angle of deflection, x is then measured.

The weight of the ball is W. show that the force of repulsion F on the suspended ball is given by:

F = W tan x"


I've drawn a free body force diagram, but i still can't work it out..
help pleaseee
 
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Start by identifying the forces acting on the suspended ball. (Hint: Three forces act on that ball.) Then apply the conditions for equilibrium: the sum of the forces must be zero. (Hint: Consider vertical and horizontal components separately.)
 
Ok I've got to the point where I've found that the components of N (the normal reaction force) are:

N sin x

and

N cos x

I don't study maths so could you please give me hints as to how I turn the above into F = W tan x?
 
I don't know what you mean by the "normal force" in this problem. Answer the questions I asked in my last post: What are the forces acting on the ball?
 
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