How Is Electric Flux Calculated Through a Cube Face with Multiple Charges?

AI Thread Summary
To calculate the electric flux through one face of a cube with a central charge and additional symmetrically placed charges, start by determining the total flux from the central charge using Gauss's law, which states that the total flux through the cube is equal to the charge enclosed divided by the permittivity of free space. The flux through one face can be found by dividing the total flux by six, as there are six faces on the cube. For the additional charges, integration is necessary to account for their contributions to the electric field and flux. The discussion emphasizes the need to correctly apply the integral for the electric field and area. Overall, understanding the contributions from both the central charge and surrounding charges is crucial for accurately calculating the electric flux.
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Homework Statement


A particle with charge Q= 5.00 microcoulombs is located at the center of a cube of edge L= 0.100 m. In addition, six other identical charged particles -q are positioned symmetrically around Q. Determine the electric flux through one face of the cube.

Homework Equations



Flux= S E dA (the S is suppose to be an integral symbol)

The Attempt at a Solution



Flux= S E dA + S E dA

is this right so far? if so not sure what I need to do next, if not what do I need to do? thanks
 
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Hi tag16! :smile:

(have an integral: ∫ :wink:)
tag16 said:
Flux = ∫ E dA + ∫ E dA

is this right so far? if so not sure what I need to do next, if not what do I need to do? thanks

For the charge at the centre, the flux is easy to find … just find the flux through all 6 faces, and divide by 6. :wink:

But for the other charges, yes, I think you'll have to do some integrating. :smile:
 

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