How Is Energy Calculated for Moving an Object Away from Earth's Surface?

aloshi
Messages
79
Reaction score
0
hi!
in my book they are trying to derive a formula for how much energy is needed to move an object height h from the Earth's surface. so large that:

dent's total work (W) spent a
to move a body with mass m from the Earth to a point at distance R from the center of the earth:
W=c\cdot m\cdot M\cdot (\frac{1}{R_0}-\frac{1}{R})
c = 6.66 * 10 ^ -11, R_0 = 6370
when R increases approaching the term 1 / R all zero, and work to keep a body from the Earth's surface infinitely far into the universe can be calculated by the formula
W=c\cdot \frac{m\cdot M}{R_0}
what I can not really understand is that work is defined as force*distance, W=F*s.
why is \frac{1}{R_0}-\frac{1}{R}=distance and why is c\cdot m\cdot M=force??

can someone explain to me, thanks

2) why is c\cdot m\cdot M the same at m\cdot g\cdot R^2_0, also
c\cdot m\cdot M=m\cdot g\cdot R^2_0
 
Last edited:
Physics news on Phys.org
Hi aloshi! :smile:

(It's not c, it's G. :wink:)

Work isn't force*distance unless the force is constant.

Work is the integral of force wrt distance … W = ∫ F.ds,

and in this case F = GMm/r2, so W = ∫ GMm/r2 dr = GMm/r + constant. :smile:
 


tiny-tim said:
Hi aloshi! :smile:

(It's not c, it's G. :wink:)

Work isn't force*distance unless the force is constant.

Work is the integral of force wrt distance … W = ∫ F.ds,

and in this case F = GMm/r2, so W = ∫ GMm/r2 dr = GMm/r + constant. :smile:
but I can not about Integration, can you explain in a different way? pleas
 


tiny-tim said:
Hi aloshi! :smile:

(It's not c, it's G. :wink:)

Work isn't force*distance unless the force is constant.

Work is the integral of force wrt distance … W = ∫ F.ds,

and in this case F = GMm/r2, so W = ∫ GMm/r2 dr = GMm/r + constant. :smile:

unless the force is not constant, way they write the worke sow??

and i find this:
W=\int_{r=R_0}^{R}Fdr=\int_{r=R_0}^{R}\frac{cmM}{r^2}dr=cmM\int_{r=R_0}^{R}\frac{1}{r^2}dr=cmM\[-\frac{1}{r}\]_{R_0}^R=cmM\(\frac{1}{R_0}-\frac{1}{R}\)
but i can not anderstund't
 
Last edited:
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top