B How is energy stored in these fields?

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Energy is stored in an electric field through capacitors, where the work done to charge the capacitor from zero to a charge Q0 is given by W = (1/2)(Q0^2/C), representing the energy stored in the electric field between the plates. In magnetic fields, inductors store energy as current flows through them, with the work required to increase the current from I to I+dI calculated as W = (1/2)LI0^2, reflecting the energy stored in the magnetic field of the coil. Gravitational fields store energy based on the height of an object above a reference point, with potential energy calculated as U = mgh, where m is mass, g is gravitational acceleration, and h is height. Each field has distinct mechanisms for energy storage, emphasizing the principles of work and resistance in electric and magnetic systems. Understanding these concepts is crucial for applications in electrical engineering and physics.
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How is energy stored in the following fields, please give an example for each field:

1. Electric field
2. Magnetic field
3. Gravitational field
 
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1. Consider a capacitor of capacitance C. The energy required to charge the capacitor to charge ##Q_0## is the energy that will be stored in the e-field between its plates. Why it is required energy to charge from charge 0 to charge ##Q_0##? Consider a capacitor that is already charged at charge ##q## and we want to charge it to charge ##q+dq##. Therefore we have to do work against the E-field that exists between its plates to transfer charge +dq from the negative plate to the positive plate and this work is ##dW=Vdq=\frac{q}{C}dq## . So the total work done to charge it from 0 to charge ##Q_0## is ##W=\int dW=\int_0^{Q_0}\frac{q}{C}dq=\frac{1}{2}\frac{Q_0^2}{C}## and this work is stored as E-field energy in the E-field between its plates.
2. Consider an inductor of inductance L. The energy required to "charge" the inductor to current ##I_0## is the energy that will be stored in the magnetic field inside the turns of the coil. Energy is required because we know that an inductor "resists" a change to its current from ##I## to ##I+dI## (due to Lenz's law). The work required to change the current from ##I## to ##I+dI## is ##dW=VIdt=L\frac{dI}{dt}Idt=LIdI## so the total work required is ##W=\int dW=\int_0^{I_0}LIdI=\frac{1}{2}LI_0^2##.
 
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Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...
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