How Is Equilibrium Achieved Between Two Blocks on an Inclined Plane?

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Equilibrium between two blocks on an inclined plane involves analyzing the forces acting on each block. Block A, with a mass of 7.52 kg, is positioned on a 30.5-degree incline, while Block B hangs vertically at the end of the incline. To determine the mass of Block B when the system is in equilibrium, a Free Body Diagram (FBD) should be drawn to visualize the forces. The equations for the sum of forces (F = ma) must be applied to solve for Block B's mass. Understanding these principles is crucial for solving the problem effectively.
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Heres a description of the diagram given. Block A is on a inclined plane at a degree of 30.5 degrees. Block B is hanging at the end of the incline plane. Both blocks are attached to the string with a pully up by the corner of the incline plane. here the problem:

Block A has a mass of 7.52 kg and is on an incline of 30.5o. If the system is in equilibrium, what is the mass of Block B?

CONFUESED please help
 
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jmatthews1967 said:
Heres a description of the diagram given. Block A is on a inclined plane at a degree of 30.5 degrees. Block B is hanging at the end of the incline plane. Both blocks are attached to the string with a pully up by the corner of the incline plane. here the problem:

Block A has a mass of 7.52 kg and is on an incline of 30.5o. If the system is in equilibrium, what is the mass of Block B?

CONFUESED please help

Welcome to the PF. Start by drawing a Free Body Diagram (FBD) of the blocks. Label all the forces, and write the equations for the sum of F = ma.
 
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