How is Force Divided Among Car Tires?

  • Context: Undergrad 
  • Thread starter Thread starter phymatter
  • Start date Start date
  • Tags Tags
    Force Tires
Click For Summary
SUMMARY

The discussion centers on how force is distributed among car tires based on the vehicle's mass and tire pressure. It is established that the total force exerted by the tires on the ground equals the weight of the car, calculated as mg, where m is the mass and g is the acceleration due to gravity. Assuming uniform conditions, the force is divided equally among the four tires, resulting in each tire supporting a force of mg/4. However, variations in engine placement and other factors can lead to unequal force distribution across the tires.

PREREQUISITES
  • Understanding of basic physics concepts such as force, mass, and pressure.
  • Knowledge of tire mechanics and their role in vehicle dynamics.
  • Familiarity with the principles of weight distribution in vehicles.
  • Basic understanding of how engine placement affects vehicle balance.
NEXT STEPS
  • Research the impact of engine placement on vehicle weight distribution.
  • Learn about tire pressure effects on vehicle handling and performance.
  • Explore advanced vehicle dynamics and load transfer during acceleration and braking.
  • Study the principles of suspension systems and their influence on tire force distribution.
USEFUL FOR

Automotive engineers, physics students, and anyone interested in vehicle dynamics and tire performance optimization.

phymatter
Messages
131
Reaction score
0
force by tires divided ?

suppose the mass of a car is m kg , the pressure in its tires is p Pa , so so balance the weight of the car the tires with contact area A will exert some force on the ground , will this force be = mg for all the tires , or will they divide the force among themselves , meaning that the force applied by each = mg/4 ??
 
Physics news on Phys.org


Assuming all things equal, they will divide the mass equally between them.

Of course, engine placement and other factors will result in different forces through each tire.
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 73 ·
3
Replies
73
Views
11K
  • · Replies 30 ·
2
Replies
30
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
13
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 51 ·
2
Replies
51
Views
5K