How Is Power Calculated for Lifting Sewage in a Pumping Station?

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To calculate the power required for lifting sewage in a pumping station, first convert the volume from liters to cubic meters, as 1 liter equals 0.001 cubic meters. The density of the sewage is given as 1,050 kg/m3, allowing for the calculation of mass from the volume. The work done by the pump can be determined by multiplying the force exerted by the pump, which must counteract gravity, by the vertical distance of 5.50 m. The power output can then be found by dividing the work done by the time taken, which is one day in this case. Understanding these relationships is crucial for solving the problem effectively.
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Homework Statement


Sewage at a certain pumping station is raised vertically by 5.50 m at the rate of 1 920 000 liters each day. The sewage, of density 1 050 kg/m3, enters and leaves the pump at atmospheric pressure and through pipes of equal diameter.


Homework Equations



p = f*d/t = work/time

The Attempt at a Solution



Find the output mechanical power of the lift station

not sure how to get power out of density and liter/day...please help
 
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Hi
What if you convert the volume given in litres to cubic meters?
 
what force is doing work when the sewage is being lifted?
 
the pump would be exerting a force upwards while gravity would be exerting a force downwards?
 
right, so how would you go about figuring out the work done by the pump on the sewage?
 
work of the pump = force of the pump * distance
 
so then, what force is the pump applying in order to move the sewage upwards against the force of gravity

remember that density is mass per unit volume and you were given the volume (a liter is just a cubic meter)
 
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