How Is Slit Width Calculated in Single Slit Diffraction?

AI Thread Summary
The discussion centers on calculating the slit width in a single slit diffraction scenario using given parameters. The wavelength of light is 460 nm, and the distance to the screen is 130 cm, with the first-order maximum positioned 2.20 mm from the central maximum. The equation used is y1 = L sin(theta) = L (wavelength / a), leading to the calculation of the slit width 'a'. A mistake was identified in converting the distance from centimeters to meters, which is crucial for accurate calculations. Correcting this conversion is essential for determining the correct slit width.
SamTsui86
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Homework Statement


A diffraction pattern is produced on a screen 130 cm from a single slit, using monochromatic light of wavelength 460 nm. The distance from the center of the central maximum to the first-order maximum is 2.20 mm. Calculate the slit width. (Hint: Assume that the first-order maximum is halfway between the first- and second-order minima.)


Homework Equations



y1 = L sin (theta) = L (wavelength / a)

The Attempt at a Solution



wavelength = 460 e -9 m
L = .13 m
y = .0022 m
so I found a

.0022 = .13 sin (theta)
sin (theta) = .0169 = (wavelength/ a)

a = .0272 mm

How anyone tell me what I am doing wrong?
 
Physics news on Phys.org
130\;cm \neq 0.13\;m

:wink:
 
oops :) my bad
 
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