How is the Electric Field Established Inside a Diode When Voltage is Applied?

AI Thread Summary
When voltage is applied to a diode, an electric field is established due to the movement of charge carriers, unlike in resistors where surface charge density creates the field. Diodes, being semiconductors, attract charge carriers to opposite polarity, leading to a built-in electric field. The relationship between electric field and voltage in this context is described by the equation E = -grad V. This process is critical for the diode's functionality in controlling current flow. Understanding this mechanism is essential for applications in electronics.
tonyjk
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Hello,

When a Voltage is applied to a diode, how the electric field is established inside the diode? Is it the same as a resistor which surface charges density establish electric field inside it?

Thanks
 
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Resistors are not semiconductors and do not attract the charge carriers to their opposite polarity pole.
 
tonyjk said:
Hello,

When a Voltage is applied to a diode, how the electric field is established inside the diode?
Ignoring variable magnetic field it is established as E = -grad V
 

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