How Is the Force on a Child in a Roller Coaster Calculated?

AI Thread Summary
To calculate the force on a child in a roller coaster at point B, the centripetal force formula Fc = (mv^2)/r is used, where the mass is 40.0 kg, speed is 15.6 m/s, and radius is 7.30 m. The child’s weight is also considered, leading to the equation Fc - mg = net force. The attempt to include a cosine factor in the equation was incorrect, as it misapplied the direction of forces. The centripetal force acts towards the center of the loop, and the net force on the child at point B should be evaluated correctly without unnecessary components. Properly calculating these forces is essential for accurate results.
Austin Gibson
Messages
47
Reaction score
1

Homework Statement

:[/B]
A child of mass 40.0 kg is in a roller coaster car that travels in a loop of radius 7.30 m. At point A the speed of the car is 15.0 m/s, and at point B, the speed is 15.6 m/s. Assume the child is not holding on and does not wear a seat belt.

What is the force (in N) of the car seat on the child at point B? (Enter the magnitude.)

0711e4f0e8708dce75c79380761364c9.png


Homework Equations


Fc = [(mv^2)/r]
Fc = ma

The Attempt at a Solution

:

I solved (a) and (c).
I solved (a) by inserting the mass, speed, and radius into the equation [(mv^2)/r] and subtracting by (mass*gravity).
My equation for (b) was [(mv^2)/r * cos30] - mg = [(40*(15.6^2)/7.3*cos30) - (40*9.8) = 762.8 N. That was incorrect. What's improper about my equation? [/B]
 

Attachments

  • 0711e4f0e8708dce75c79380761364c9.png
    0711e4f0e8708dce75c79380761364c9.png
    16.8 KB · Views: 2,904
Physics news on Phys.org
Austin Gibson said:

Homework Statement

:[/B]
A child of mass 40.0 kg is in a roller coaster car that travels in a loop of radius 7.30 m. At point A the speed of the car is 15.0 m/s, and at point B, the speed is 15.6 m/s. Assume the child is not holding on and does not wear a seat belt.

What is the force (in N) of the car seat on the child at point B? (Enter the magnitude.)

View attachment 232155

Homework Equations


Fc = [(mv^2)/r]
Fc = ma

The Attempt at a Solution

:[/B]

I solved (a) and (c).
I solved (a) by inserting the mass, speed, and radius into the equation [(mv^2)/r] and subtracting by (mass*gravity).
My equation for (b) was [(mv^2)/r * cos30] - mg = [(40*(15.6^2)/7.3*cos30) - (40*9.8) = 762.8 N. That was incorrect. What's improper about my equation? [/B]
In what direction is the centripetal force at point B ?

Also, is there any net force on the child at point B ?
 
  • Like
Likes Austin Gibson
SammyS said:
In what direction is the centripetal force at point B ?
120 degrees(90+30)?
 
I solved it by applying (cos 30) to mg instead of the centripetal force.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top