How is the Formula (1+x+x^2+...+x^n^-^2+x^n^-^1)^2 Expanded?

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Can you tell me what the following formula will be after it gets expanded ?
(1+x+x^2+...+x^n^-^2+x^n^-^1)^2 = ?

Thanks a lot,
 
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What's written inside the parantheses is a geometric series. It's equal to (1 - x^(n - 1 + 1)) / (1 - x). Now just square it...
 
Thanks a lot,
 

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