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omc1
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How Is the Mass of Each Hailstone Calculated?
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To calculate the mass of each hailstone, the volume of a sphere formula is used, resulting in a volume of approximately 5.58 cm³ for a hailstone with a diameter of 2.2 cm. Multiplying this volume by the density of hail (0.92 g/cm³) gives a mass of about 5.13 grams per hailstone. The initial calculation mistakenly multiplied the mass of one hailstone by the total number of stones, leading to confusion. The correct mass of each hailstone is confirmed to be 5.13 grams. This highlights the importance of careful attention to detail in calculations.
… each hailstone! 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19.
For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Let's declare that for the cylinder,
mass = M = 10 kg
Radius = R = 4 m
For the wall and the floor,
Friction coeff = ##\mu## = 0.5
For the hanging mass,
mass = m = 11 kg
First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on.
Force on the hanging mass
$$mg - T = ma$$
Force(Cylinder) on y
$$N_f + f_w - Mg = 0$$
Force(Cylinder) on x
$$T + f_f - N_w = Ma$$
There's also...
This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is
The second part of the problem is exactly why you get this affect.
And one more spoiler:
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