How is this simplification possible?

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The function x(t) = (148/3)e^(-6t) + 1 describes the amount of salt in a tank over time. At t = 40, the term (148/3)e^(-240) becomes extremely small, approximately 2.67E(-103), making its contribution negligible. Consequently, the function approaches an asymptotic value of 1, as the small number added to 1 does not significantly alter its value. This highlights the limitations of numerical precision in calculations, especially when dealing with very small values. Therefore, while it does not strictly "simplify to 1," it can be treated as approximately equal to 1 in practical scenarios.
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x(t) = (148/3)e^(-6t) + 1

I am trying to find the amount of salt (x) in the tank at time = 40.

Out of interest I checked it out on wolframalpha, and
(148/3)e^(-240) is around 2.67E(-103) SO RIDICULOUSLY SMALL
but as soon as put the 'plus 1' on the end, it someone all simplifies down to 1?
How is that possible...? thanks!
 
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One plus a very small number is one. The function starts out at ~50 at t=0 and decreases very rapidly to an asympotic value of 1.
 
In addition, computers typically can't handle numbers with that many digits. Rounding has to occur unless you are using a special math library with provision for very long numbers.

Fred
 
To put this into perspective, x(2) = 1.003...
Which means that unless you go to 4 significant figures or more, you won't see a difference.
And most experiments in a lab is only 3 significant figures.

As you have shown, (148/3)e^(-240) only differs from zero in the 102nd decimal place.
You need to think about why you would ever need precision to that level.
 
Strictly speaking, it does NOT "simplify to 1". It is approximately equal to 1 and, depending on the situation can be treated as 1.
 
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