How Is Torque Calculated on a Rectangular Coil in a Magnetic Field?

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To calculate the torque on a rectangular coil in a magnetic field, the relevant formula is τ = N * B * I * A * sin(θ), where N is the number of turns, B is the magnetic field strength, I is the current, A is the area of the coil, and θ is the angle between the normal to the coil and the magnetic field. For a coil with 25 turns, a magnetic field of 0.8T, a current of 12A, and an angle of 30 degrees, the area A can be calculated as 0.04m * 0.04m. The confusion arises from the application of the force on a current-carrying wire, which is not necessary when using the torque formula directly. The correct approach involves substituting the values into the torque equation to find the torque acting on the coil.
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Homework Statement


A rectangular coil consists of 25 turns of wire forming a square 4cm each side. By considering the force on a current-carrying straight wire, calculate the torque acting on the coil when the normal is at 30 degrees to a magnetic field of 0.8T and 12 A are flowing.


Homework Equations



t = ucrossB

F = IlcrossB

The Attempt at a Solution



Umm I am a bit stuck with this as I do now know why I am meant to be using the force acting on the current carrying wire. I thought I could just use the t = ucrossB forumla in the form:

t = ubsintheta

where u = IA

However this clearly isn't correct so I am looking for some help! Thanks
 
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Torque τ = ΝΒΙΑsin(θ)
 

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