TheJoninator
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In a light bulb, is the filament made up of elements which each produce a colour of visible light to make white?
White light is produced by the uniform emission of all frequencies within the visible light spectrum from a light bulb's filament, typically made of Tungsten. The power spectral density of the emitted light is uniform, stimulating all cones in the human eye equally. Each wavelength, defined by the equation λ = c/v, where c is the speed of light and v is frequency, corresponds to different energy levels governed by Planck's constant (E = hv). Tungsten's high melting point allows it to emit a wide range of photon energies, resulting in the production of white light through black body radiation.
PREREQUISITESStudents of physics, electrical engineers, lighting designers, and anyone interested in the principles of light and color production in various materials.
mscudder3 said:White light is seen by the human eye because all frequencies (each color) are being produced. More formally, the power spectral density is uniform over the visible light spectrum. This means that each of the eye's cones are stimulated equally. Therefor the filament of a light bulb is emitting energies uniformly across the visible light energy spectrum. Each wavelength (which defines color) is given by lamda=c/v, where c is the speed of light and v is the frequency. This frequency is directly related to the energy of the light wave by Planck's constant, h (E=hv). Thus, each characteristic energy (in the visible light spectrum) is being emitted by the element. In the case of conventional filaments, this element is Tungsten. Due to the high melting point of tungsten, the variety of photon emissions is large enough to cover the visible light spectrum (since they are dependent on temperature).
Hope this helps!
TheJoninator said:Ok, but how can one element emit different frequency photons? I thought that each element only emitted one frequency of photon?