How Long Before an Oscillator's Energy Halves?

AI Thread Summary
The discussion revolves around calculating the time it takes for the energy of an oscillator to halve, given a mass on a spring with a specific oscillation period and a reduction factor due to friction. The initial approach incorrectly interpreted "t" as time in seconds instead of the number of cycles. After clarification, it was understood that the correct calculation involves determining the number of cycles required for energy decay and then converting that to time using the oscillation period. The user successfully resolved the problem after receiving guidance. The thread highlights the importance of correctly interpreting variables in physics equations.
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Homework Statement



A mass M is suspended from a spring and oscillates with a period of .940s. Each complete oscillation results in an amplitude reduction of a factor of .96 due to a small velocity dependent of frictional effect. Calculate the time it takes for the total energy of the oscillator to decrease to .50 of its initial value.

Homework Equations



unsure... A=Ao*factor^N

The Attempt at a Solution



I am unsure how to approach this. I did

log .50 = t log(.96)^2
t= log(.50)/log(.96)^2
t=8.48 s

but that was incorrect. Can someone please tell me what I am doing wrong?
 
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In you equation

log .50 = t log(.96)^2,

"t" isn't the time in seconds, it's the number of cycles of oscillation when the energy has decayed to .50 of the original value.

You want to time for 8.48 cycles with a period of 0.940 sec/cycle.
 
Oh, I see now. I think I can handle the equation from here. Well, I'm going to attempt the problem again to make sure :smile:
 
Yes, I got it correct, thank you AlephZero!
 
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