How long before the box hits the ground?

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A plane traveling at 100 m/s drops a box from an elevation of 2000 meters. Assuming no air resistance, the box's fall is governed by the equation for freefall, where the acceleration due to gravity is 9.8 m/s². The time to reach the ground can be calculated using the formula 4.9t² = 2000, leading to a specific time for the fall. The horizontal speed of the plane does not affect the time it takes for the box to hit the ground, as the fall is determined solely by vertical motion. The discussion clarifies the importance of focusing on vertical acceleration rather than horizontal displacement.
unidentified4789
A plane is traveling at 100m/s when it drops a box at an elevation of 2000 meters. How much time is required for the box to reach the earth?
 
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You know the equation for freefall? Apply it to find the time and multiply the time by the speed of the plane.
 
What assumptions are you making? Are you ignoring air resistance? (If not, then you will have to state what the air resistance is.)

Assuming no air resistance, 2000 m is low enough that we can ignore the change in gravitational force due to change in distance so: the acceleration is 9.8 m/s2. The downward speed after time t is 9.8 t m/s and the distance fallen is 4.9 t2. The box will hit the Earth when 4.9 t2= 2000.

The information about the horizontal speed of the airplane (and therefore the horizontal speed of the box) is irrelevant. The time to hit depends only on vertical acceleration and speed.
 
As someone informed me in a pm, I misread the problem. Sorry. Halls had it right. I was thinking of how far the box would move forward.
 
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