How Long Does a Ball Take to Fall Back Down After Being Thrown Upward?

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A ball is thrown upward with an initial velocity of 25 m/s and is caught 5 m above the ground. To determine the time of flight and the velocity upon descent, the kinematic equation y = Vi*t - 1/2*g*t^2 is used. Substituting the known values for y, initial velocity (Vi), and gravitational acceleration (g), the equation can be solved for time (t). The solution yields two values for t, with the larger value representing the total time of flight. The final velocity upon descent can also be calculated using kinematic principles.
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Homework Statement


A boy throws a ball vertically upward from the ground with the velocity 25 m/s. On its way down it is caught 5 m above the ground. How long did the trip take and with what velocity was it coming down?


Homework Equations





The Attempt at a Solution


Which equation of motion should I use? Please give me hints
 
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Use
y = Vi*t - 1/2*g*t^2.
Solve the quadratic to find t. You will get two values. For return journey, take the larger value of t.
 
What do you mean by solve the quadratic for t?
 
manzoor said:
What do you mean by solve the quadratic for t?
In the problem y is given. g is known. Initial velocity is given. Substitute these values in the kinematic equation and solve for t.
 

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