How Long Does a Ball Thrown 60 Feet Up Take to Land?

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To determine how long a ball thrown 60 feet into the air takes to land, the student attempts to use the equation x = V(o)T + 1/2(a)T, where x is the final position, V(o) is the initial velocity, T is time, and a is acceleration. The student incorrectly calculates the time, leading to a negative value, indicating a misunderstanding of the physics involved. To solve for time accurately, the correct approach involves setting the equation to account for the total displacement of 60 feet and solving for T with the appropriate values for initial velocity and acceleration due to gravity. The discussion highlights the need for clarification on the correct application of the kinematic equations. Understanding these principles is essential for solving similar physics problems effectively.
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Homework Statement


A student throws a ball 60 ft into the air

a)How long does he have to wait to catch it on the way down? <----Just needing help on this!
b)What was its initial velocity?<----and this if a) was solved.
c)What will be its final velocity?


Homework Equations


x=V(o)T + 1/2(a)T

x = Final Position
V(o) = Initial Velocity
T = Time (assuming final)
a=acceleration




The Attempt at a Solution



Attempt was not full proof but was the only way "I" could think of but I know its wrong.

1st Step: 120 ft. = (0 ft/s)T + 1/2(-32 ft/s^(2))T
2nd Step: 120 ft. = T + (-16ft/s^(2))T ;Zero disappeared. Multiplied 1/2(-16).
3rd Step: (120 ft.)/ (-16 ft/s^(2)) = 2T ; Dividing 120/-16. Added Both Time(T) together.
4th Step: (-7.5 s^(2)) / (2)=T
5th Step: Got -3.75 s^(2) = T

Optional Step: Square root -3.75 s^(2) = Nevermind...Thats why I need help. Can someone walk me through this. Thank You
 
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