How Long Does an Interstellar Cloud Take to Contract?

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An interstellar cloud with a radius of 10 parsecs and a mass of 10,000 solar masses is analyzed for its contraction time. Assuming zero initial velocity and constant density, the free-fall time can be estimated using the formula sqrt(R^3/GM). Given the parameters, the calculated free-fall time is approximately 29.6 million years. The mass-to-radius ratio suggests the cloud is slightly above the average interstellar medium density, yet it remains a valid scenario for collapse. This analysis provides insight into the timescales involved in the contraction of such interstellar clouds.
knhlove
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Problem:"An interstellar cloud with a radius of 10parsecs and a mass of 10000 Msun is contracting. How long does this take? (The cloud itself has no pressure)
 
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knhlove said:
Problem:"An interstellar cloud with a radius of 10parsecs and a mass of 10000 Msun is contracting. How long does this take? (The cloud itself has no pressure)

Assuming it begins at zero velocity and constant density then its freefall time is ~sqrt(R^3/GM) but the size you've quoted sounds a tad excessive for the mass you quote if it's a gravitationally bound mass. The cloud is only about double the average ISM. But let's use those numbers because it's going to collapse at some temperature assuming no other masses interfering with it. So the radius is 2062648 AU and the mass is 10,000 suns. Thus free-fall time in Gaussian years is sqrt(2062648^3/10,000) = 29.6 million years.
 
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