How Long Does It Take for an Object to Fall to the Ground?

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An object falling to the ground can have its fall time calculated using the formula t = √(2h/g), where h is the height and g is the acceleration due to gravity. Assuming no friction and an initial velocity of zero, this equation allows for determining both the time of descent and the final velocity just before impact. The discussion confirms that the height is the distance from the object to the ground. Participants clarify the equations related to free fall, emphasizing the role of gravitational attraction. Understanding these principles enables accurate predictions of fall duration and impact speed.
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Hi,

If you no the height of an object only, assuming no frictional forces, and that it is on earh. Can you determine how long it will take to hit the ground?

Thanks
James
 
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Also the final velocity is also unknown and the initial velocity is zero?
 
I am assuming that you're talking about the height between the object and the floor. The answer is yes, and that is obvious from the equations that describe free fall, meaning the fall that is induced and preserved only by the force of gravitational attraction that the Earth exerts on the body.

So we have
h = \frac{1}{2} g t^2 \Leftrightarrow t = \sqrt{\frac{2h}{g}}
and since you know h, you can calculate the required time. Using that t you can solve for the final velocity of the body, the one it has right before it reaches ground. And yes, since you let the body go at one point without pushing it downwards, the initial velocity is zero.
 
Last edited:
karkas said:
I am assuming that you're talking about the height between the object and the floor. The answer is yes, and that is obvious from the equations that describe free fall, meaning the fall that is induced and preserved only by the force of gravitational attraction that the Earth exerts on the body.

So we have
h = \frac{1}{2} g t^2 \Leftrightarrow t = \sqrt{2gh}
and since you know h, you can calculate the required time. Using that t you can solve for the final velocity of the body, the one it has right before it reaches ground. And yes, since you let the body go at one point without pushing it downwards, the initial velocity is zero.

No t=square root (2h/g)
velocity = square root (2gh)
 
Yes sorry my bad.
 
Thanks for the reply's guys, much help :smile:
 
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