How long does it take for rotating platform to stop

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To determine how long it takes for a rotating platform to stop, the final angular velocity (\omega) is zero when the platform ceases rotation. The equation used is 0 = \omega_0 + \alpha t, where \alpha is negative due to the decrease in angular speed. The initial angular speed (\omega_0) is given as 8π, and the angular acceleration (\alpha) is -1.96 rad/s². By substituting these values into the equation, the time (t) can be calculated. This approach clarifies why the solution manual simplified the equation by omitting the non-zero final angular velocity.
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Hi my problem is I have a platform that is rotating and it \omega_0=8\pi and the question is how long does it take it to stop. All my work up to here is correct and I have \sum\tau=I\alpha where my \sum\tau=3.75Nm and I=1.91kgm^2 and \alpha=1.96rad/s^2 so I wanted to use the \omega= \omega_0+\alpha t equation but i don't know final angular velocity and time is my target variable. The solution manual used \omega=\alpha t why is this justified? The \omega_0 does not equal zero so why did the solution manual just take it out?
 
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Alem2000 said:
Hi my problem is I have a platform that is rotating and it \omega_0=8\pi and the question is how long does it take it to stop. ...
I wanted to use the \omega= \omega_0+\alpha t equation but i don't know final angular velocity .

The final state is when the platform stops, it means does not rotate, is not the final angular velocity zero then? :smile:

ehild
 
The final \omega is zero. So you have
0=\omega_0+\alpha t
\alpha is actually negative (angular speed decreasing), and you know the initial angular speed, so solve the above equation for t and you're done.
 
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