How long does it take for the sun to produce 10,000 KWh on a 31,700 m² surface?

  • Thread starter Thread starter Dassinia
  • Start date Start date
  • Tags Tags
    Energy Time
AI Thread Summary
To determine how long it takes for the sun to produce 10,000 KWh on a 31,700 m² surface, the relationship between energy and power is crucial. Power is defined as energy divided by time, which can be expressed as P = E/t. The Stefan-Boltzmann law provides the power radiated per unit area, allowing for the calculation of total power by multiplying by the surface area. By rearranging the equation, time can be calculated as t = E/(σ*T^4*31,700). Understanding these principles enables the accurate calculation of the required time for energy production.
Dassinia
Messages
141
Reaction score
0
Hello

Homework Statement


How much time does it take to the sun to furnish an energy of 10 000 KWh on a surface of 31 700 m².


Homework Equations


Stefan-Boltzman law ?
the power radiated from a black body = σ*T4



The Attempt at a Solution


I don't know how I can find the time, I don't know any equation that depend on t to find it, if someone can explain me, that would be great !
Thank you !
 
Physics news on Phys.org
Hmm, so you don't know where time comes in? You know the total energy that must be provided. You also know the power. What is the relationship between energy and power? This will answer your question...
 
Hello,
Pavg=E/τ ?
 
Yes, generally power = energy/time (power is the RATE at which energy is produced or expended). So, given that information, how would you solve for time?

Also, you are missing one other thing: the Stefan-Boltzman law give you the power radiated PER unit area from a blackbody emitter. So how would you determine the total power radiated in this situation?
 
t=E/(σ*T4*31700) ?
Thanks
 
Or I have to use
P=dE/dt
P*dt=dE
∫Pdt=E
∫(σ*T4*31700)dt=E ?
But integrating from what to what ?
 
Dassinia said:
t=E/(σ*T4*31700) ?

Thanks

Yes.

Dassinia said:
Or I have to use
P=dE/dt
P*dt=dE
∫Pdt=E
∫(σ*T4*31700)dt=E ?
But integrating from what to what ?

No, you don't have to integrate, because the power is constant with time, so your equation becomes P = dE/dt = ΔE/Δt, and all you have to to is solve for Δt, as you did above.
 
Ah OK ,
Thank you cepheid !
 
Back
Top